$$P(response)=1-[1+dose\frac{2^{\frac{1}{a}}-1}{N^{50}} ]^{-a}$$
Submitted by admin on Mon, 08/07/2017 - 09:04
Submitted by admin on Mon, 08/07/2017 - 09:04
Submitted by admin on Mon, 08/07/2017 - 09:04
Submitted by admin on Mon, 08/07/2017 - 09:04
Submitted by admin on Mon, 08/07/2017 - 09:04
Submitted by admin on Mon, 08/07/2017 - 09:04
Submitted by admin on Mon, 08/07/2017 - 09:04
Submitted by admin on Mon, 08/07/2017 - 09:04
Submitted by admin on Mon, 08/07/2017 - 09:04
Submitted by admin on Mon, 08/07/2017 - 09:04